(2x-3)*(4x^2-9)=0

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Solution for (2x-3)*(4x^2-9)=0 equation: 


Simplifying
(2x + -3)(4x2 + -9) = 0

Reorder the terms:
(-3 + 2x)(4x2 + -9) = 0

Reorder the terms:
(-3 + 2x)(-9 + 4x2) = 0

Multiply (-3 + 2x) * (-9 + 4x2)
(-3(-9 + 4x2) + 2x * (-9 + 4x2)) = 0
((-9 * -3 + 4x2 * -3) + 2x * (-9 + 4x2)) = 0
((27 + -12x2) + 2x * (-9 + 4x2)) = 0
(27 + -12x2 + (-9 * 2x + 4x2 * 2x)) = 0
(27 + -12x2 + (-18x + 8x3)) = 0

Reorder the terms:
(27 + -18x + -12x2 + 8x3) = 0
(27 + -18x + -12x2 + 8x3) = 0

Solving
27 + -18x + -12x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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